You are given three integer arrays of the same length: counts, xs, and ys. For each index i, there are counts[i] people located at the point (xs[i], ys[i]) on a grid.
Choose a meeting point (x, y) (any pair of integers) that minimizes the total travel cost, where each person's cost is the Manhattan distance from their location to the meeting point:
Input: counts = [1, 2], xs = [1, 3], ys = [1, 3]
Output: 4
Explanation: Meeting at (3, 3): the 1 person at (1, 1) travels |3-1| + |3-1| = 4,
and the 2 people at (3, 3) travel 0. Total = 1*4 + 2*0 = 4. No point does better.